# Programmer: Sriram Pemmaraju
# Date: 3/5/2015

# This function "rounds" a given floating point number to the nearest "half integer"
# provided the "half integer" is within distance 1/1000 and it returns that half integer. 
# Otherwise, the function returns None. By half integers, we mean elements in the set
# {...-1.5, -1. -0.5, 0, 0.5, 1, 1.5,...}
def nearHalfInteger(f):

    # We compute three candidates to compare f to
    # Note that we have to pay attention to whether
    # f is negative
    x = int(f)
    if x >= 0:
        y = x + 1/2
        z = x + 1
    else:
        y = x - 1/2
        z = x - 1

    # We check if there is candidate at distance <= 1/1000
    # and if so, return it.
    if abs(f - x) <= 1/1000:
        return x
    elif abs(f - y) <= 1/1000:
        return y
    elif abs(f - z) <= 1/1000:
        return z

    return None

# main program
n = int(input())

# Now read the remaining input; we expect there to be
# n floating point numbers in the input
counter = 0
numHalfInts = 0 # keeps track of number of near half ints
while counter < n:
    f = float(input())
    if nearHalfInteger(f) != None:
        numHalfInts = numHalfInts + 1
        
    counter = counter + 1
    
print("The number of near half integers is", numHalfInts)